(4x^2-4x+6)/(2x+3)

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Solution for (4x^2-4x+6)/(2x+3) equation:


D( x )

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:+oo)

(4*x^2-(4*x)+6)/(2*x+3) = 0

(4*x^2-4*x+6)/(2*x+3) = 0

4*x^2-4*x+6 = 0

2*(2*x^2-2*x+3) = 0

2*x^2-2*x+3 = 0

DELTA = (-2)^2-(2*3*4)

DELTA = -20

DELTA < 0

2 = 0

2/(2*x+3) = 0

x belongs to the empty set

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